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y^2+17y-60=0
a = 1; b = 17; c = -60;
Δ = b2-4ac
Δ = 172-4·1·(-60)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*1}=\frac{-40}{2} =-20 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*1}=\frac{6}{2} =3 $
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